20y^2-20y-5=20

Solution for 20y^2-20y-5=20 equation:

20y^2-20y-5=20

We move all terms to the left:

20y^2-20y-5-(20)=0

We add all the numbers together, and all the variables

20y^2-20y-25=0

a = 20; b = -20; c = -25;
Δ = b2-4ac
Δ = -202-4·20·(-25)
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20\sqrt{6}}{2*20}=\frac{20-20\sqrt{6}}{40}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20\sqrt{6}}{2*20}=\frac{20+20\sqrt{6}}{40}
$